python实现简单flappybird-创新互联

本文实例为大家分享了python实现flappy bird的简单代码，供大家参考，具体内容如下

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import pygame
from pygame.locals import *
from sys import exit
import random
 
# 屏幕宽度
SCREENWIDTH = 288
# 屏幕高度
SCREENHEIGHT = 512
IMAGES = {}
# 背景图片地址
BACKGROUND_PATH = 'back_ground.png'
PIPE_PATH = 'pipe.png'
BASE_PATH = 'base.png'
PLAYER_PATH = (
  'bird2_0.png',
  'bird2_1.png',
  'bird2_2.png',
)
# 初始化
pygame.init()
# 创建窗口
SCREEN = pygame.display.set_mode((SCREENHEIGHT, SCREENHEIGHT))
# 设置窗口标题
pygame.display.set_caption("Flappy Bird")
 
# 加载图片,透明用convert_alpha,不透明用convert
IMAGES['background'] = pygame.image.load(BACKGROUND_PATH).convert()
IMAGES['base'] = pygame.image.load(BASE_PATH).convert_alpha()
IMAGES['bird'] = (
  pygame.image.load(PLAYER_PATH[0]).convert_alpha(),
  pygame.image.load(PLAYER_PATH[1]).convert_alpha(),
  pygame.image.load(PLAYER_PATH[2]).convert_alpha(),
)
IMAGES['pipe'] = (
  pygame.transform.rotate(pygame.image.load(PIPE_PATH).convert_alpha(), 180),
  pygame.image.load(PIPE_PATH).convert_alpha()
 
)
BASEY = SCREENHEIGHT * 0.82
 
# 设置帧率
FPS = 30
FPSCLOCK = pygame.time.Clock()
 
PIPE_WIDTH = IMAGES['pipe'][0].get_width()
PIPE_HEIGHT = IMAGES['pipe'][0].get_height()
PLAYER_WIDTH = IMAGES['bird'][0].get_width()
PLAYER_HEIGHT = IMAGES['bird'][0].get_height()
 
 
PIPEGAPSIZE = 100 # 两个水管之间的距离
x = SCREENWIDTH//2
y = SCREENHEIGHT//2
move_x = 0
move_y = 0
 
flap = 0 # 小鸟初始状态
pipeVelX = -4 # 管道x方向的速度
playerVelY = 0 # 小鸟y方向的初速度
playerMaxVelY = 10 # 小鸟y方向的大速度
playerMinVelY = -8 # 小鸟y方向的最小速度
playerAccY = 2 # 小鸟y方向的下降加速度
playerFlapAcc = -3 # 小鸟y方向的上升加速度
playerFLapped = False # 当小鸟飞的时候为真
playery = int((SCREENHEIGHT - PLAYER_HEIGHT)/2)
 
 
# 随机移动柱子
def getRandomPipe():
  # 两个水管之间的距离有如下变量
  gapYs = [20, 30, 40, 50, 60, 70, 80, 90]
  index = random.randint(0, len(gapYs) - 1)
  gapY = gapYs[index]
 
  gapY += int(BASEY * 0.2)
  # 水管x坐标
  pipeX = SCREENWIDTH + 10
 
  return [
    {'x': pipeX, 'y': gapY - PIPE_HEIGHT},  # 上面水管的左上角位置
    {'x': pipeX, 'y': gapY + PIPEGAPSIZE},  # 下面水管的左上角位置
  ]
 
 
 
 
newPipel = getRandomPipe()
 
upperPipes = [
  {'x': SCREENWIDTH, 'y':newPipel[0]['y']}
]
lowerPipes = [
  {'x': SCREENWIDTH, 'y':newPipel[1]['y']}
]
 
while True:
 
  for event in pygame.event.get():
    if event.type == QUIT:
      exit()
    elif event.type == KEYDOWN:
      if event.key == K_LEFT:
        move_x = -3
      elif event.key == K_RIGHT:
        move_x = 3
      elif event.key == K_UP:
        move_y = -3
      elif event.key == K_DOWN:
        move_y = 3
    elif event.type == KEYUP:
      move_x = 0
      move_y = 0
 
  x = x + move_x
  y = y + move_y
 
  # 防止冲出边界
  if x > SCREENWIDTH:
    x = 0
  elif x < 0:
    x = SCREENWIDTH
 
  if y > SCREENHEIGHT:
    y = 0
  elif y < 0:
    y = SCREENHEIGHT
 
  # 贴图在左上角
  SCREEN.blit(IMAGES['background'], (0, 0)) # 背景
  # 显示水管
  for uPipe, lPipe in zip(upperPipes, lowerPipes):
    SCREEN.blit(IMAGES['pipe'][0], (uPipe['x'], uPipe['y']))
    SCREEN.blit(IMAGES['pipe'][1], (lPipe['x'], lPipe['y']))
 
 
 
  # 放小鸟
  SCREEN.blit(IMAGES['bird'][flap], (x, y))
  flap = flap + 1
 
  if flap % 3 == 0:
    flap = 0
 
 
  for uPipe, lPipe in zip(upperPipes, lowerPipes):
    uPipe['x'] += pipeVelX
    lPipe['x'] += pipeVelX
 
 
  # 当水管移动到某一位置的时候，生成新的水管
 
  if 0 < upperPipes[0]['x'] < 5:
    newPipe = getRandomPipe()
    upperPipes.append(newPipe[0])
    lowerPipes.append(newPipe[1])
  
 
  # 如果水管从右往左移动到边缘，则摧毁水管
  if upperPipes[0]['x'] < -PIPE_WIDTH:
    # 队列头出队
    upperPipes.pop(0)
    lowerPipes.pop(0)
 
 
  # 刷新画面
  pygame.display.update()
  FPSCLOCK.tick(FPS)

文章标题：python实现简单flappybird-创新互联
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