189 8069 5689

vb.net矩阵的运算 vb求逆矩阵

vb.net中矩阵计算问题请教高手.

给你一个函数 Public Sub Vect1XtoVect2(ByVal x1 As Double, ByVal y1 As Double, ByVal z1 As Double, _ ByVal x2 As Double, ByVal y2 As Double, ByVal z2 As Double, _ ByRef xNew As Double, ByRef yNew As Double, ByRef zNew As Double) '矢量叉积 xNew = y1 * z2 - z1 * y2 yNew = z1 * x2 - x1 * z2 zNew = x1 * y2 - y1 * x2 End Sub其中x1,y1,z1为第一个矢量,x2,y2,z2为第二个矢量xnew,ynew,znew为得到的新矢量

十余年的石台网站建设经验,针对设计、前端、开发、售后、文案、推广等六对一服务,响应快,48小时及时工作处理。成都全网营销的优势是能够根据用户设备显示端的尺寸不同,自动调整石台建站的显示方式,使网站能够适用不同显示终端,在浏览器中调整网站的宽度,无论在任何一种浏览器上浏览网站,都能展现优雅布局与设计,从而大程度地提升浏览体验。创新互联建站从事“石台网站设计”,“石台网站推广”以来,每个客户项目都认真落实执行。

用vb.net编程,建立一个m行n列的矩阵,找出其中最小的元素所在的行和列,并输出该值及其行、列位置

没错!!

你的算法是:

1.定义三个变量,minValue(放最小值),X(放最小值的X坐标),Y(放最小值的Y坐标)。

2.遍历矩阵。在遍历过程中将最小值放在minValue中,最小值的X坐标放在X中,最小值的Y坐标放在X中。

求助!用Vb.net编写两个矩阵相乘!

Public Shared Sub Main()

Dim a As Integer, b As Integer, c As Integer, d As Integer

Console.WriteLine("该程序将求出两个矩阵的积:")

Console.WriteLine("请指定矩阵A的行数:")

a = Integer.Parse(Console.ReadLine())

Console.WriteLine("请指定矩阵A的列数:")

b = Integer.Parse(Console.ReadLine())

Dim MatrixA As Integer(,) = New Integer(a - 1, b - 1) {}

For i As Integer = 0 To a - 1

For j As Integer = 0 To b - 1

Console.WriteLine("请输入矩阵A第{0}行第{1}列的值:", i + 1, j + 1)

MatrixA(i, j) = Integer.Parse(Console.ReadLine())

Next

Next

Console.WriteLine("矩阵A输入完毕.")

Console.WriteLine("请指定矩阵B的行数:")

c = Integer.Parse(Console.ReadLine())

Console.WriteLine("请指定矩阵B的列数:")

d = Integer.Parse(Console.ReadLine())

Dim MatrixB As Integer(,) = New Integer(c - 1, d - 1) {}

For i As Integer = 0 To c - 1

For j As Integer = 0 To d - 1

Console.WriteLine("请输入矩阵A第{0}行第{1}列的值:", i + 1, j + 1)

MatrixB(i, j) = Integer.Parse(Console.ReadLine())

Next

Next

Console.WriteLine("矩阵B输入完毕.")

Console.WriteLine("矩阵A为:")

outputMatrix(MatrixA, a, b)

Console.WriteLine("矩阵B为:")

outputMatrix(MatrixB, c, d)

If b c Then

Console.WriteLine("矩阵A的列数与矩阵B的行数不相等,无法进行乘积运算!")

Return

Else

Console.WriteLine("矩阵A与矩阵B的乘积为:")

End If

Dim MatrixC As Integer(,) = New Integer(a - 1, d - 1) {}

For i As Integer = 0 To a - 1

For j As Integer = 0 To d - 1

MatrixC(i, j) = 0

For k As Integer = 0 To b - 1

MatrixC(i, j) += MatrixA(i, k) * MatrixB(k, j)

Next

Next

Next

outputMatrix(MatrixC, a, d)

End Sub

Private Shared Sub outputMatrix(MatrixX As Integer(,), rowCount As Integer, columnCount As Integer)

For i As Integer = 0 To rowCount - 1

For j As Integer = 0 To columnCount - 1

Console.Write(MatrixX(i, j) vbTab)

Next

Console.WriteLine()

Next

End Sub

End Class


本文题目:vb.net矩阵的运算 vb求逆矩阵
网站地址:http://cdxtjz.cn/article/hipeso.html

其他资讯