189 8069 5689

Java编写父节点代码 js父节点

id为表中的主键 name是要显示的内容,Fid代表组织的父节点,使用JAVA编写函数,以树形结构的形式打印输出

可以通过关系映射查询出来 请看下面

网站制作、成都网站制作的开发,更需要了解用户,从用户角度来建设网站,获得较好的用户体验。创新互联建站多年互联网经验,见的多,沟通容易、能帮助客户提出的运营建议。作为成都一家网络公司,打造的就是网站建设产品直销的概念。选择创新互联建站,不只是建站,我们把建站作为产品,不断的更新、完善,让每位来访用户感受到浩方产品的价值服务。

在mybatis中,没有级联的概念,但是可以利用集合来实现类似的功能。

mybatis3.0添加了association和collection标签专门用于对多个相关实体类数据进行级联查询,但仍不支持多个相关实体类数据的级联保存和级联删除操作。因此在进行实体类多对多映射表设计时,需要专门建立一个关联对象类对相关实体类的关联关系进行描述。

插入关联表:

insert id="insertWife" useGeneratedKeys="true" keyProperty="wid" parameterType="com.cssl.pojo.Wife"

insert into wife (name,h_id) values (#{name},#{husband.hid})

/insert

关联映射:嵌入式、继承式 引入式等

先在数据库建立好主外键关系

在xml里面写一个resultMap作为返回类型,如果是多对一 用association 一对多用collection

例子

!-- 多对一 --

resultMap id="wifeandhusband" type="wife"

id property="wid" column="wid"/id

result property="wname" column="wname"/result

association property="husband" column="w_hid" javaType="com.cssl.pojo.Husband"

id property="hid" column="hid"/id

result property="name" column="name"/result

/association

/resultMap

!-- 一对多 --

resultMap id="husbandandwife" type="com.cssl.pojo.Husband"

id property="hid" column="hid"/id

result property="name" column="name"/result

collection property="wifes" ofType="wife" --ofType集合中的类型

id property="wid" column="wid"/id

result property="wname" column="wname"/result

/collection

/resultMap

select id="selectWife" resultMap="wifeandhusband"

select w.*,h.* from wife w left join husband h on w.h_id=h.hid

/select

注意:

1、关联查询一定要带有关联对象的id(主外键),否则集合只会有一条记录存在(认为你查询的是一个对象)

如:

select h.name,h.age,w.wname from wife w left join husband h on h.hid=w.h_id

2、表连接中不同表有同名字段的时候:a和b都有name字段

resultMap type="b" id="b"

id property="bid" column="id"/

result property="name" column="name"/

association property="a" javaType="a"

id property="aid" column="aid"/

result property="name" column="aname"/

/association

/resultMap

select id="select" resultMap="b"

select a.id aid,a.name aname,b.id,b.name from a,b where a.id=b.id

/select

java 获取xml 父节点 并追加

你用什么解释xml啊,

子结点。append属性,然后父节点。append子结点啊。

求数据结构二叉树查找结点及其父节点的代码,谢谢!!!

#includeiostream

#includemap

using namespace std;

const int N=15e3+100;

struct node{

int v;//结点值

int l,r;//左右孩子的下标

st()

{//初始化

l=r=-1;

}

}tree[4*N];//4倍空间,用来储存二叉树

mapint,intmp;//储存数值在数组a中的下标

int a[N];//基础数组,数组tree在其基础上建树

int n=1;//1 5 8 0 0 0 6 0 0

void build_tree(int rt,int num)

{//构建二叉树

if(a[num]==0)

{//a[num]==0,表示空结点

tree[rt].v=-1;

}

else

{

if(mp.count(a[num])==0)

mp[a[num]]=rt;//储存a[num]在树中的位置

tree[rt].v=a[num];//结点赋值

num++;

build_tree(2*rt,num);//左孩子

num++;

build_tree(2*rt+1,num);//右孩子

}

}

/*

1 5 8 0 0 0 6 0 0

3

8 1 6

*/

int main()

{

int x=1,m=0;

do

{

cina[n++];//储存结点值

}

while(getchar()!='\n');//回车结束输入

build_tree(1,x);//构建二叉树(结构体数组模拟)

cinm;//查询次数

for(int i=0;im;i++)

{

int num,y;

cinnum;//查询值

y=mp[num];//mp[num]是num在tree数组中的位置,查询效率O(log2n)

y/=2;//左右孩子的下标除以2,就是父节点的下标

if(y==0)

{//父节点下标为0,既是根节点

cout0endl;

}

else

{//输出父节点值

couttree[y].vendl;

}

}

return 0;

}

JAVA父类及子类的声明编程题(编写的代码行后面要配有必要的注释)

程序如下供你参考.说明:

1.0 你题目中只提供了两门成绩,英语和计算机,但是下面说三门.

如果是的话,自己添加上去吧.很好修改的.

2.0 如果有什么不清楚的话,补充问题吧.或者可以给你留言.

3.0 希望你自己多看书把语言的基础知识学好.

下面共四个java类文件.

/***Student.java **/

public class Student {

protected int studentID;

protected String name;

protected int englishScore;

protected int computerScore;

protected int totalScore;

public Student(int studentID, String name) {

super();

this.studentID = studentID;

this.name = name;

}

public Student(int studentID, String name, int englishScore,

int computerScore) {

super();

this.studentID = studentID;

this.name = name;

this.englishScore = englishScore;

this点抗 puterScore = computerScore;

}

public int getStudentID() {

return studentID;

}

public void setStudentID(Integer studentID) {

this.studentID = studentID;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public int getEnglishScore() {

return englishScore;

}

public void setEnglishScore(int englishScore) {

this.englishScore = englishScore;

}

public int getComputerScore() {

return computerScore;

}

public void setComputerScore(int computerScore) {

this点抗 puterScore = computerScore;

}

public int getTotalScore() {

return totalScore;

}

/**totalScore 没有set 方法 */

@Override

public String toString() {

return "Student [studentID=" + studentID + ", name=" + name

+ ", englishScore=" + englishScore + ", computerScore="

+ computerScore + ", totalScore=" + totalScore + "]";

}

@Override

public boolean equals(Object obj) {

if (this == obj)

return true;

if (obj == null)

return false;

if (getClass() != obj.getClass())

return false;

Student other = (Student) obj;

if (name == null) {

if (other.name != null)

return false;

} else if (!name.equals(other.name))

return false;

if (studentID != other.studentID)

return false;

return true;

}

/** @return 返回1 表示 大于,返回 0 表示等于, 返回-1表示小于 */

public int compare(Student other){

if(totalScore other.totalScore)

return -1; //

if(totalScore == other.totalScore)

return 0;

return 1;

}

private void sum(){

totalScore = englishScore+computerScore;

}

/**计算评测成绩 */

public double testScore(){

return (englishScore+computerScore)/2;

}

}

/***** StudentXW.java******/

public class StudentXW extends Student {

private String response;///责任

public StudentXW(int studentID, String name, String response) {

super(studentID, name);

this.response = response;

}

public StudentXW(int studentID, String name, int englishScore,

int computerScore, String response) {

super(studentID, name, englishScore, computerScore);

this.response = response;

}

public String getResponse() {

return response;

}

public void setResponse(String response) {

this.response = response;

}

@Override

public double testScore(){

return (englishScore+computerScore)/2+3;

}

}

/*****StudentBZ.java****/

public class StudentBZ extends Student {

private String response;///责任

public StudentBZ(int studentID, String name, String response) {

super(studentID, name);

this.response = response;

}

public StudentBZ(int studentID, String name, int englishScore,

int computerScore, String response) {

super(studentID, name, englishScore, computerScore);

this.response = response;

}

public String getResponse() {

return response;

}

public void setResponse(String response) {

this.response = response;

}

@Override

public double testScore(){

return (englishScore+computerScore)/2+5;

}

}

/*****测试类 TestStudent.java****/

/** Student ,StudentXW, 及StudentBZ测试类 */

public class TestStudent {

public static void main(String[] args) {

Student s1 = new Student(1,"one");

s1.setEnglishScore(80);

s1.setComputerScore(80);

StudentXW sx1 = new StudentXW(2,"xone","学习委员");

sx1.setEnglishScore(90);

sx1.setComputerScore(90);

StudentBZ sb1 = new StudentBZ(3,"bone","班长");

sb1.setEnglishScore(70);

sb1.setComputerScore(70);

System.out.println("学生 One 的评测成绩为:"+s1.testScore());

System.out.println("学生 xone,学习委员的评测成绩为:"+sx1.testScore());

System.out.println("学生 bone,班长的评测成绩为:"+sb1.testScore());

Student [] studentArray = new Student[5];

studentArray[0] = new Student(101,"studentOne",60,60);

studentArray[1] = new Student(102,"studentTwo",65,65);

studentArray[2] = new Student(103,"studentThree",70,70);

studentArray[3] = new StudentXW(104,"studentXW",75,75,"学习委员");

studentArray[4] = new StudentBZ(104,"studentXW",80,80,"学习委员");

for(Student student:studentArray){

System.out.println("名字为:"+student.getName()+"的成绩为:"+ student.testScore());

}

}

}


当前文章:Java编写父节点代码 js父节点
本文链接:http://cdxtjz.cn/article/ddehogi.html

其他资讯