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利用JavaScript制作一个纸牌发牌动画？很多新手对此不是很清楚，为了帮助大家解决这个难题，下面小编将为大家详细讲解，有这方面需求的人可以来学习下，希望你能有所收获。
技术概要
1.对象操作
2.数据操作
3.JS animation动画
4.全局变量
function desen_x(){
let that = this;
var desen=["h_1","h_2","h_3","h_4","h_5","h_6","h_7","h_8",
"h_9","h_10","h_11","h_12","h_13","p_1","p_2","p_3","p_4"
,"p_5","p_6","p_7","p_8","p_9","p_10","p_11","p_12","p_13"
,"t_1","t_2","t_3","t_4","t_5","t_6","t_7","t_8","t_9","t_10"
,"t_11","t_12","t_13","x_1","x_2","x_3","x_4","x_5","x_6","x_7"
,"x_8","x_9","x_10","x_11","x_12","x_13"];
//将你的扑克前戳名全部存储到数组中
var Obj = new Object(); //新建一个对象
var array=[];//空数组一个
for(var i=0;i<4;i++){//游戏演示里只需要发4张扑克，所以只要<4
var x=Math.round(Math.random()*52);//随机数取整*52
Obj[i]=x;//存入到全局变量中 否则每次只能存一个数值
}
console.log(Obj);//打印对象看看是不是4个对象
window.array=[desen[Obj[0]],desen[Obj[1]],desen[Obj[2]],desen[Obj[3]]];
//将存好的数组 带入扑克全局
}function send_poker(){ //该方法是发牌事件
console.log(window.array);
//测试你的全局变量是否正常
//并且将传递的全局变量带入temp[]
var temp=[window.array[0],window.array[1],window.array[2],window.array[3]];
var ti=0;
var iamges="../poker/"+temp+".png";//这是图片的默认路径 +你的 desen
var creator=document.getElementById("d_back"); //取得操作的dom父元素
var po_1=document.createElement("div");//虚拟生成div
var num = 0; //初始化变量
//po_1.src="../h_1.png";
//img_1.scr="../images/poker/h_1.png";
for(var i=0;i动画事件
function move_poker(){ //移动扑克
var node = document.getElementById("d_back").childNodes;//获取父元素下的所有子节点
console.log(node);//打印出有多少
var n5=node[9];//以要操作的 img对象类为 9开始操作
var n6=node[10];
var n7=node[11];
var n8=node[12];
var popo=anime({//animation动画可在最后查看
targets: n5, //操作的对象
translateX:-150, //移动到的横向位置
translateY: -250,//移动到的纵向位置
easing: 'easeInOutQuad',//缓动，不更改css机制
duration:100,//完成时间
});
var popo1= anime({
targets: n6,
translateX:-100,
translateY: -250,
easing: 'easeInOutQuad',
duration:200,
});
var popo2=anime({
targets: n7,
translateX:-50,
translateY: -250,
easing: 'easeInOutQuad',
duration:300,
});
var popo3= anime({
targets: n8,
translateX:0,
translateY: -250,
easing: 'easeInOutQuad',
duration:400,
});
}
function gui(){ //GUI 是将所有节点复位，方便下次发牌
var node = document.getElementById("d_back").childNodes;
var n5=node[9];
var n6=node[10];
var n7=node[11];
var n8=node[12];
var popo4=anime({
targets: [n5,n6,n7,n8],
translateX:0,
translateY: 0,
})
node.removeChild(popo4);
}animation封装
function setAnimationsProgress(insTime) { //该方法有多个dom时，则执行异或异步线程模式进行
var i = 0;
var animations = instance.animations;
var animationsLength = animations.length;
while (i < animationsLength) {
var anim = animations[i];
var animatable = anim.animatable;
var tweens = anim.tweens;
var tweenLength = tweens.length - 1;
var tween = tweens[tweenLength];
if (tweenLength) { tween = filterArray(tweens, function (t) { return (insTime < t.end); })[0] || tween; }
var elapsed = minMax(insTime - tween.start - tween.delay, 0, tween.duration) / tween.duration;
var eased = isNaN(elapsed) ? 1 : tween.easing(elapsed);
var strings = tween.to.strings;
var round = tween.round;
var numbers = [];
var toNumbersLength = tween.to.numbers.length;
var progress = (void 0);
for (var n = 0; n < toNumbersLength; n++) {
var value = (void 0);
var toNumber = tween.to.numbers[n];
var fromNumber = tween.from.numbers[n] || 0;
if (!tween.isPath) {
value = fromNumber + (eased * (toNumber - fromNumber));
} else {
value = getPathProgress(tween.value, eased * toNumber);
}
if (round) {
if (!(tween.isColor && n > 2)) {
value = Math.round(value * round) / round;
}
}
numbers.push(value);
}
var stringsLength = strings.length;
if (!stringsLength) {
progress = numbers[0];
} else {
progress = strings[0];
for (var s = 0; s < stringsLength; s++) {
var a = strings[s];
var b = strings[s + 1];
var n$1 = numbers[s];
if (!isNaN(n$1)) {
if (!b) {
progress += n$1 + ' ';
} else {
progress += n$1 + b;
}
}
}
}
setProgressValue[anim.type](animatable.target, anim.property, progress, animatable.transforms);
anim.currentValue = progress;
i++;
}
}看完上述内容是否对您有帮助呢？如果还想对相关知识有进一步的了解或阅读更多相关文章，请关注创新互联行业资讯频道，感谢您对创新互联网站建设公司，的支持。
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