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#include windows.h
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LRESULT CALLBACK WndProc(HWND, UINT, WPARAM, LPARAM);
int WINAPI WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance,
PSTR szCmdLine, int iCmdShow)
{
static TCHAR szAppName[]=TEXT("二次函数");
HWND hwnd;
MSG msg;
WNDCLASS wndclass;
wndclass.style=CS_HREDRAW|CS_VREDRAW;
wndclass.lpfnWndProc=WndProc;
wndclass.cbClsExtra=0;
wndclass.cbWndExtra=0;
wndclass.hInstance=hInstance;
wndclass.hIcon=LoadIcon(NULL, IDI_APPLICATION);
wndclass.hCursor=LoadCursor(NULL, IDC_ARROW);
wndclass.hbrBackground=(HBRUSH)GetStockObject(WHITE_BRUSH);
wndclass.lpszMenuName=NULL;
wndclass.lpszClassName=szAppName;
if (!RegisterClass(wndclass))
{
MessageBox(NULL, TEXT("Error"),
szAppName, MB_ICONERROR);
return 0;
}
hwnd=CreateWindow(szAppName, TEXT("二次函数"),
WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT, CW_USEDEFAULT,
CW_USEDEFAULT, CW_USEDEFAULT,
NULL, NULL, hInstance, NULL);
ShowWindow(hwnd, iCmdShow);
UpdateWindow(hwnd);
while (GetMessage(msg, NULL, 0, 0))
{
TranslateMessage(msg);
DispatchMessage(msg);
}
return msg.wParam;
}
LRESULT CALLBACK WndProc(HWND hwnd, UINT message, WPARAM wParam, LPARAM lParam)
{
static int cxClient, cyClient;
const static int n=1000;
HDC hdc;
int i;
PAINTSTRUCT ps;
POINT apt[n];
switch (message)
{
case WM_SIZE:
cxClient=LOWORD(lParam);
cyClient=HIWORD(lParam);
return 0;
case WM_PAINT:
hdc=BeginPaint(hwnd, ps);
MoveToEx(hdc, 0, cyClient/2, NULL);
LineTo(hdc, cxClient, cyClient/2);
MoveToEx(hdc, cxClient/2, 0, NULL);
LineTo(hdc, cxClient/2, cyClient);
for (i=0; i n;++i)
{
apt[i].x=cxClient/4+i; apt[i].y=cyClient-(cyClient/2-i)*(cyClient/2-i)/300-cyClient/2+100;
}
Polyline(hdc, apt, n);
return 0;
case WM_DESTROY:
PostQuitMessage(0);
return 0;
}
return DefWindowProc(hwnd, message, wParam, lParam);
}
用GDI绘图吧，比较简单。绘图的思想是让x以固定的值在区间内持续增长，比如x=0.1,0.2,0.3.....，以计算出的y值来确定y坐标。用线连接所有的点就行了。MoveTo()，LineTo（）函数你用得着，具体情况请自行查看MSDN。
和数学上一样啊 来个坐标x，y 分别表示列和行 。在函数上就打印一个* 给个范围，双层循环加条件就可以了
我画了半个正弦函数，其余的你可以照着画，欢迎讨论，
#include "stdio.h"
#include "conio.h"
#include "math.h"
#include "graphics.h"
void main()
{
int driver,mode,i;
driver=DETECT;
mode=0;
initgraph(driver,mode,"");
setcolor(15);
for(i=0;i360;i++)
line(i,200*sin(i*3.14/360),i+1,200*sin((i+1)*3.14/360));
getch();
restorecrtmode();
}
你要什么图像 sin 还cos 要不我都给你把！
1、#includestdio.h
#includemath.h
void main()
{
double y;
int i,n;
for(y=1;y=0;y-=0.1)
{n=asin(y)*10;
for(i=1;i=n;i++)
printf(" ");
printf("*");
for(;i=31-n;i++)
printf(" ");
printf("*\n");}
for(y=0;y=1;y+=0.1)
{n=asin(y)*10;
for(i=-1;i=31+n;i++)
printf(" ");
printf("*");
for(;i=62-n;i++)
printf(" ");
printf("*\n");}
}
2、#includestdio.h
#includemath.h
void main()
{
double y;
int x,m;
for(y=1;y=-1;y-=0.1)
{m=acos(y)*10;
for(x=1;xm;x++)
printf(" ");
printf("*");
for(;x62-m;x++)
printf(" ");
printf("*\n");}
}
之后在给你个连个图像相交的把
3、#includestdio.h
#includemath.h
void main()
{
double y;
int n,m,i,j,x,yy;
for(yy=0;yy=20;yy++)
{ y=0.1*yy;
m=acos(1-y)*10;
n=asin(1-y)*10;
i=32+asin(y-1)*10;
j=61-asin(y-1)*10;
for(x=0;x62;x++)
{if((x==n)(x==m)) printf("+");
else if((x==n)||(x==i)||(x==j)) printf("+");
else if((x==m)||(x==62-m)) printf("*");
else printf(" ");}
printf("\n");
}
}
需要Window图像编程，Window编程就是基于C语言的，在Visual C++6.0可以编写Win32程序