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Try this one,should be fine
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下面这个已经有排序了哦，不行么？
SELECT uid, group_concat(subject)
FROM (SELECT id, uid, subject
FROM (SELECT id, uid, subject,
(SELECT COUNT(*)
FROM t_subject
WHERE uid = t.uid
AND subject = t.subject) RK
FROM t_subject t) t1
WHERE rk = 3) t2
GROUP BY uid
多了个a.原来
或者你直接用个substring()得了。。。
select * from
(select Student.S#,Sname,Sage,Ssex,SC.C#,score,Cname
from SC inner join Student on SC.S#=Student.S#
inner join Course on Course.C#=SC.C#) as t
where exists(
select count(1) from t as d
where C#=d.C# and score d.score
having count(1)3
)
select class,total,name from (select *,ywsc+sxsc as total from st ORDER BY total DESC) b
where
not EXISTS(select * from (select *,ywsc+sxsc as total from st ORDER BY total DESC) c where c.class=b.class and b.total c.total GROUP BY c.class HAVING COUNT(*)2 )
ORDER BY b.class,b.total DESC
上面那条答案应该是可以的啊，可能是看起来复杂了点吧，我自己试过是没问题的：
SELECT t1.sno,t1.cno,Score
FROM SC t1
WHERE EXISTS
(SELECT COUNT(1)
FROM SC
WHERE t1.cno= cno AND t1.scorescore
HAVING COUNT(1)3)
ORDER BY t1.cno,score DESC
另外还有一种类似的写法：
SELECT t1.sno,t1.cno,Score
FROM SC t1
WHERE
(SELECT COUNT(cno)
FROM SC
WHERE t1.cno= cno AND t1.scorescore)3
ORDER BY t1.cno,score DESC