189 8069 5689
第一个：
公司主营业务：做网站、网站设计、移动网站开发等业务。帮助企业客户真正实现互联网宣传，提高企业的竞争能力。成都创新互联是一支青春激扬、勤奋敬业、活力青春激扬、勤奋敬业、活力澎湃、和谐高效的团队。公司秉承以“开放、自由、严谨、自律”为核心的企业文化，感谢他们对我们的高要求，感谢他们从不同领域给我们带来的挑战，让我们激情的团队有机会用头脑与智慧不断的给客户带来惊喜。成都创新互联推出灵台免费做网站回馈大家。
#include stdio.h
main()
{
float s=0.0,t=0.0;
printf("gongzi:\n");
scanf("%f",s);
if (s0)
printf("0");
else if (s1000)
{t=0.0 ;
printf("gongzi:%5.2f,shui:%5.2f,shifagongzi:%5.2f",s,t,s-t); }
else if (s=1000 s2000)
{t=s*0.05;
printf("gongzi:%5.2f,shui:%5.2f,shifagongzi:%5.2f",s,t,s-t); }
else if (s=2000 s3000)
{t=s*0.08;
printf("gongzi:%5.2f,shui:%5.2f,shifagongzi:%5.2f",s,t,s-t); }
else if (s=3000 s5000)
{t=s*0.10;
printf("gongzi:%5.2f,shui:%5.2f,shifagongzi:%5.2f",s,t,s-t); }
else if (s=5000)
{t=s*0.15;
printf("gongzi:%5.2f,shui:%5.2f,shifagongzi:%5.2f",s,t,s-t); }
getch();
}
第2个：
main()
{
int day,x1,x2;
day=9;
x2=1;
while(day0)
{x1=(x2+1)*2;/*第一天的桃子数是第2天桃子数加1后的2倍*/
x2=x1;
day--;
}
printf("the total is %d\n",x1);
第3个：
#include stdio.h
#define N 3
#define M 3
main()
{
int a[N][M],sum[N]={0};
double avg[N];
int i,j;
for(i=0;iN;i++)
{
printf("Input the %dth student's scores:",i+1);
for(j=0;jM;j++)
{
scanf("%d",a[i][j]);
sum[i]+=a[i][j];
}
avg[i]=(double)sum[i]/M;
}
printf("The sums are:");
for(i=0;iN;i++)
printf("%4d",sum[i]);
printf("\nThe averages are:");
for(i=0;iN;i++)
printf("%6.2lf",avg[i]);
printf("\n");
}
第4个：
#define N 4
int array[N][N];
void convert(int array[3][3]) /*函数类型可定义为void，也可用默认的int*/
{int i,j,t; /*因为函数形实参是数组，按地址传递*/
/*两个数组所用空间相同，函数无需返回值*/
for(i=0;iN;i++)
for(j=i+1;jN;j++) /* j=i+1防止两元素对调后再次恢复原位 */
{t=array[i][j];
array[i][j]=array[j][i];
array[j][i]=t;
}
}
main()
{
int i,j;
void convert(int [][]); /*注意此处的 [ ][ ] 形式，表明是二维数组*/
printf("Input array:\n"); /* 因为函数原型处仅检查形参个数、类型名、
for(i=0;iN;i++) /* 顺序，而不检查形参名。所以只写成[ ][ ] 形式
for(j=0;jN;j++) /* 即可。仅对void时如此，对int似乎不成立？*/
scanf("%d",array[i][j]);
printf("\noriginal array:\n");
for(i=0;iN;i++)
{for(j=0;jN;j++)
printf("%5d",array[i][j]);
printf("\n");
}
convert(array);
printf("convert array:\n");
for(i=0;iN;i++)
{for(j=0;jN;j++)
printf("%5d",array[i][j]);
printf("\n");
}
}
第5个：
#define nmax 50
main()
{
int i,k,m,n,num[nmax],*p;
printf("please input the total of numbers:");
scanf("%d",n);
p=num;
for(i=0;in;i++)
*(p+i)=i+1;
i=0;
k=0;
m=0;
while(mn-1)
{
if(*(p+i)!=0) k++;
if(k==3)
{ *(p+i)=0;
k=0;
m++;
}
i++;
if(i==n) i=0;
}
while(*p==0) p++;
printf("%d is left\n",*p);
}
你看懂了吗？看懂就送分吧
如果看不懂你就是瞎问
再送点详解给你
#include stdio.h
#define N 50 // 排队人数(可任意更改)
#define CAL 3 //凡报3的人出列(可任意更改)
//下面是排队编号函数:从h 开始的n个人依次编号1到n
void stdline(int *h,int n)
{
int i;
for(i=1;in+1;i++) *(h+i-1)=i;
}
/*下面函数表示从指针h处开始的人数为boy个人排队，从1报数，每报到call的人出列*/
void outline(int *h,int boy,int call)
{
int *p, chu, callnum;
/*说明:
p 工作指针，表示从头依次指向每个元素，点名
chu 计数器，记录出列的人数
callnum 计数器，记录点名次序
*/
chu=0;
callnum=0;//各计数器清零
p=h; //开始时，工作指针指向数组首
printf("出列顺序是：\n");
while(chuboy)
{
if(*p!=0) callnum++; //每次加报数
if(callnum==call) //如果某一个人报到出列数call...
{
printf("%5d",*p); //打印编号，表示出列
chu++; //出列人数加1
if(chu==boy)//如果全部出列....
{
*h=*p; //把最后一个出列人的编号记入地址开始处
return; //结束
}
if(chu%10==0)printf("\n");//每输出10个换行
callnum=0; //出列后,重新报数
*p=0; //出列后,将其编号赋零,以示区别
}
p++; //工作指针移向下一个人,即下一个数组元素
if(ph+boy-1)p=h;/*如果移到最后一个元素的后面,则让指向地址开头继续报数*/
}
}
void main()
{
int a[N]; //用数组模拟队列,每个元素代表一个人
stdline(a,N);//编号
outline(a,N,CAL);//计算并打印出列顺序
printf("\n最后留下来的是 %d 号\n",*a);/*在函数中,已经把最后一个人的编号写入了数组首地址处,
这里输出就可以了*/
}
第6个：
#includestdio.h
struct date
{
int year;
int month;
int day;
}date;
void main()
{
int sum=0,leap;
printf("\n请输入日期（年,月,日）\n");
scanf("%d,%d,%d",date.year,date.month,date.day);
switch(date.month)//先计算某月以前月份的总天数。
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf("data error");
break;
}
sum=sum+date.day;//再加上某天的天数。
if(date.year%400==0||(date.year%4==0date.year%100!=0))
leap=1;
else
leap=0;
if(leap==1date.month2)//如果是闰年且月份大于2,总天数应该加一天。
sum++;
printf("这天是当年的第 %d 天。\n",sum);
}
写不下了。。。
你看我的理解对不。如果有问题，HI我。
/*表达的有点不清楚，如果x是20000，按10%算还是按20%算*/
#includestdio.h
int main(void)
{
double tax=0,money,m;
int c;
printf("请输入全年应纳所得额数目:\n");
scanf("%lf",money);
m=money;
if(money/100008)
c=8;
else
c=(int)money/10000;
switch(c)//找到一个入口，顺次相加各个级应纳税额。
{
case 8:tax+=(money-80000)*0.35;money=80000;
case 7:
case 6:
case 5:
case 4:tax+=(money-40000)*0.30;money=40000;
case 3:
case 2:tax+=(money-20000)*0.20;money=20000;
case 1:tax+=(money-10000)*0.10;money=10000;
case 0:tax+=money*0.05;break;
default:printf("Data Error!\n");
}
printf("应纳税额:%.2f\n",tax);
printf("最终所得:%.2f\n",m-tax);
return 0;
}
为了便于你验证程序执行结果：下面的可以多次执行，直到你输入的money不大于0.
#includestdio.h
int main(void)
{
while(1)
{
double tax=0,money,m;
int c;
printf("请输入全年应纳所得额数目:\n");
scanf("%lf",money);
if(money=0)
break;
m=money;
if(money/100008)
c=8;
else
c=(int)money/10000;
switch(c)//找到一个入口，顺次相加各个级应纳税额。
{
case 8:tax+=(money-80000)*0.35;money=80000;
case 7:
case 6:
case 5:
case 4:tax+=(money-40000)*0.30;money=40000;
case 3:
case 2:tax+=(money-20000)*0.20;money=20000;
case 1:tax+=(money-10000)*0.10;money=10000;
case 0:tax+=money*0.05;break;
default:printf("Data Error!\n");
}
printf("应纳税额:%.2f\n",tax);
printf("最终所得:%.2f\n",m-tax);
}
return 0;
}
是调用函数，接收返回值吗？用
变量类型名 变量名=函数名(参数列表);
如:
int r;
int F(int n)
{
return n*100;
}
r=F(6);
实用计算器之程序设计
[摘 要]多用计算器的构思及设计代码
[关键词]多用计算器；设计
数值计算可以说是日常最频繁的工作了，WIN98提供了“计算器”软件供用户使用，该软件可以处理一般的一步四则运算，例如：3+2、5/3等等，但在日常中用户经常遇到多步四则运算问题，例如：3+4*5-4/2，45*34/2+18*7等等，那么该个计算器就无法胜任了，作者制作了一个实用的计算器，该计算器新增不少功能：（程序界面如图）
1．可以实现连续的四则运算
2．可以实现输入式子的显示
3．可以方便计算个人所得税
4．鼠标、键盘均可输入数据
5．操作界面友好
6．击键可发声
构建该个计算器所需研究及解决的核心问题有如下几个：1、连乘求值?2、字符显示 3、键盘输入?4、击键发声?5、个人所得税法规，为了使大家对程序有更一步认识，现将代码提供给读者参考：
*定义数组及窗体变量
Dim number2(0 To 50) As Double
Dim number(0 To 50) As Double
Dim z As Integer
Dim k As Integer, r As Integer
Dim j As Integer
Dim str As String
*调用名为“playsound”的API函数
Private Declare Function PlaySound Lib "winmm.dll" Alias "PlaySoundA" (ByVal lpszName As String, ByVal hModule As Long, ByVal dwFlags As Long) As Long
Private Const SND_FILENAME = H20000?
Private Const SND_ASYNC = H1?
Private Const SND_SYNC = H0
*判断通用过程
Sub pianduan(p As String)
r = 0
Dim i As Integer, l As Integer, h As Integer
h = 0
i = 1
If InStr(Trim$(p), "*") 0 Then
k = k + 1
End If
If InStr(Trim$(p), "/") 0 Then
r = r + 1
End If
End Sub
*连乘通用过程(略)
*各按钮事件过程
Private sub Command1_Click(Index As Integer)
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text1.Text = Text1.Text + Command1(Index).Caption
Text2.Text = Text2.Text + Command1(Index).Caption
Text1.SetFocus
End Sub
rivate sub Command10_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
str = Text3.Text
End Sub
Private sub Command11_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text3.Text = str
End Sub
rivate sub Command2_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
Text1.SetFocus
End Sub
rivate sub Command3_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text "-"
z = z + 1
Text1.SetFocus
End Sub
Private sub Command4_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
Text1.SetFocus
End Sub
rivate sub Command5_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text2.Text = Text2 + "/"
Text1.Text = Text1 + "/"
Text1.SetFocus
End Sub
Private sub Command6_Click()
PlaySound App.Path "\sound.wav", 0, SND_SYNC
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu 0 Then
Text3.ForeColor = HFF
Else
Text3.ForeColor = HFF0000
End If
Text3.Text = dengyu
Text1.SetFocus
If Len(Text3.Text) = 14 Then
calcresult.Show
End If
End Sub
rivate sub Command7_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End Sub
rivate sub Command8_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
If Val(Text3.Text) = 0 Then
MsgBox "除数不能为0！"
Exit Sub
End If
Text3.Text = 1 / Val(Text3.Text)
End Sub
Private sub Command9_Click()
PlaySound App.Path "\start.wav", 0, SND_SYNC
Text3.ForeColor = HFF0000
Text3.Text = Val(Text3.Text) * Val(Text3.Text)
End Sub
rivate sub muninternet_Click()
Dim i
i = Shell("C:\Program Files\InternetExplorer\iexplore.exe", vbMaximizedFocus)
End Sub
rivate sub munmp3_Click()
Dim i
i = Shell("C:\Program Files\Windows Media Player\mplayer2", vbNormalNoFocus)
End Sub
Private sub munsm_Click()
Dialog.Show
End Sub
rivate sub muntax_Click()
tax.Show
End Sub
rivate sub munver_Click()
ver.Show
End Sub
rivate sub notepad_Click()
Dim i
i = Shell("c:\windows\notepad", vbNormalFocus)
End Sub
Private sub Text1_KeyPress(KeyAscii As Integer)
PlaySound App.Path "\start.wav", 0, SND_SYNC
Dim num As Integer
num = Val(KeyAscii)
If num 47 And num 58 Then
Text1.Text = Text1.Text + CStr(num - 48)
Text2.Text = Text2.Text + CStr(num - 48)
End If
If num = 46 Then
Text1.Text = Text1.Text + "."
Text2.Text = Text2.Text + "."
End If
If KeyAscii = 43 Then
Dim totle As Double
Dim n As Integer
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "+"
z = z + 1
End If
If KeyAscii = 45 Then
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
Text2.Text = Text2 + "-"
Text1.Text = Text1.Text "-"
z = z + 1
End If
If KeyAscii = 42 Then
Text2.Text = Text2.Text + "*"
Text1.Text = Text1.Text + "*"
End If
If KeyAscii = 47 Then
Text2.Text = Text2.Text + "/"
Text1.Text = Text1.Text + "/"
End If
If KeyAscii = vbKeyReturn Then
PlaySound App.Path "\sound.wav", 0, SND_SYNC
Call pianduan(Text1.Text)
If k = 1 Or r = 1 Then
Call liancheng(totle)
number2(z) = totle
If Mid$(Trim$(Text1.Text), 1, 1) = "-" Then
number2(z) = -totle
End If
k = 0: r = 0
Else
number2(z) = Val(Text1.Text)
End If
Text1.Text = ""
z = z + 1
Dim dengyu As Double
Dim v As Integer
For v = 0 To 50
dengyu = dengyu + number2(v)
Next v
If dengyu 0 Then
Text3.ForeColor = HFF
Else
Text3.ForeColor = HFF0000
End If
Text3.Text = dengyu
End If
If KeyAscii = vbKeyEscape Then
z = 0: k = 0: r = 0: j = 0
Dim i As Integer
For i = 0 To 50
number(i) = 0
number2(i) = 0
Next i
Text1.Text = ""
Text2.Text = ""
Text3.Text = ""
Text1.SetFocus
End If
If Len(Text3.Text) = 14 Then
calcresult.Show
End If
End Sub
rivate sub Text3_Change()
tax2.Text1 = Text3.Text
End Sub