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Private Sub Form_Click()
Dim X(7) As Integer, Y(7) As Integer, i%
Form1.Scale (-15, 15)-(15, -15)
Form1.Line (0, 0)-(15, 0)
Form1.Line (0, 15)-(0, 0)
For i = 0 To 12 'Step 1.2 'X轴坐标
Form1.Line (i, 0.1)-(i, 0)
CurrentX = i
CurrentY = -1
Form1.Print i
Next i
For i = 0 To 12 'Step 1.2 'Y轴坐标
Form1.Line (0, i)-(0.3, i)
CurrentX = -0.5
CurrentY = i
Form1.Print i
Next i
X(0) = 0: X(1) = 2: X(2) = 4: X(3) = 6: X(4) = 8: X(5) = 10: X(6) = 12: X(7) = 14
Y(0) = 0: Y(1) = 1: Y(2) = 3: Y(3) = 4: Y(4) = 3: Y(5) = 2: Y(6) = 1: Y(7) = 0
For i = 0 To 7
Form1.PSet (X(i), Y(i)), vbRed
Next i
End Sub
Function hypot(ByVal X As Single, ByVal Y As Single)
hypot = Sqr(X ^ 2 + Y ^ 2)
End Function
Sub tspLine(ByVal n As Integer, ByVal ch As Integer, ByVal tx1 As Single, ByVal tx2 As Single, ByVal ty1 As Single, ByVal ty2 As Single)
Dim a(1000) As Single, b(1000) As Single, c(1000) As Single, dX(1000) As Single, dY(1000) As Single
Dim qx(1000) As Single, qy(1000) As Single
Dim tt As Single, bx3 As Single, bx4 As Single, by3 As Single, by4 As Single
Dim cx As Single, cy As Single, t(1000) As Single, px(1000) As Single, py(1000) As Single
Dim u(3000) As Single, v(3000) As Single, i As Integer
num = 0
For i = 1 To n
t(i) = hypot(X(i) - X(i - 1), Y(i) - Y(i - 1))
Next i
Select Case ch
Case 0 '抛物条件
u(0) = (X(1) - X(0)) / t(1): u(1) = (X(2) - X(1)) / t(2)
u(2) = (u(1) - u(0)) / (t(2) + t(1))
tx1 = u(0) - u(2) * t(1)
u(0) = (Y(1) - Y(0)) / t(1): u(1) = (Y(2) - Y(1)) / t(2)
u(2) = (u(1) - u(0)) / (t(2) + t(1))
ty1 = u(0) - u(2) * t(1)
u(0) = (X(n) - X(n - 1)) / t(n): u(1) = (X(n - 1) - X(n - 2)) / t(n - 1)
u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))
tx2 = u(0) + u(2) * t(n)
u(0) = (Y(n) - Y(n - 1)) / t(n): u(1) = (Y(n - 1) - Y(n - 2)) / t(n - 1)
u(2) = (u(0) - u(1)) / (t(n) + t(n - 1))
ty2 = u(0) + u(2) * t(n)
Case 1 '夹持条件
a(0) = 1: c(0) = 0: dX(0) = tx1: dY(0) = ty1
a(n) = 1: b(n) = 0: dX(n) = tx2: dY(n) = ty2
Case 2 '自由条件
a(0) = 2: c(0) = 1
dX(0) = 3 * (X(1) - X(0)) / t(1): dY(0) = 3 * (Y(1) - Y(0)) / t(1)
a(n) = 2: b(n) = 1
dX(n) = 3 * (X(n) - X(n - 1)) / t(n): dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)
Case 3 '循环条件
a(0) = 2: c(0) = 1
dX(0) = 3 * (X(1) - X(0)) / t(1) - (t(1) * (X(2) - X(1)) / t(2) - X(1) + X(0)) / (t(1) + t(2))
dY(0) = 3 * (Y(1) - Y(0)) / t(1) - (t(1) * (Y(2) - Y(1)) / t(2) - Y(1) + Y(0)) / (t(1) + t(2))
a(n) = 2: b(n) = 1
dX(n) = 3 * (X(n) - X(n - 1)) / t(n)
dX(n) = dX(n) + (X(n) - X(n - 1) - t(n) * (X(n - 1) - X(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))
dY(n) = 3 * (Y(n) - Y(n - 1)) / t(n)
dY(n) = dY(n) + (Y(n) - Y(n - 1) - t(n) * (Y(n - 1) - Y(n - 2)) / t(n - 1)) / (t(n) + t(n - 1))
End Select
'计算方程组系数阵和常数阵
For i = 1 To n - 1
a(i) = 2 * (t(i) + t(i + 1)): b(i) = t(i + 1): c(i) = t(i)
dX(i) = 3 * (t(i) * (X(i + 1) - X(i)) / t(i + 1) + t(i + 1) * (X(i) - X(i - 1)) / t(i))
dY(i) = 3 * (t(i) * (Y(i + 1) - Y(i)) / t(i + 1) + t(i + 1) * (Y(i) - Y(i - 1)) / t(i))
Next i
'采用追赶法解方程组
c(0) = c(0) / a(0)
For i = 1 To n - 1
a(i) = a(i) - b(i) * c(i - 1): c(i) = c(i) / a(i)
Next i
a(n) = a(n) - b(n) * c(i - 1)
qx(0) = dX(0) / a(0): qy(0) = dY(0) / a(0)
For i = 1 To n
qx(i) = (dX(i) - b(i) * qx(i - 1)) / a(i)
qy(i) = (dY(i) - b(i) * qy(i - 1)) / a(i)
Next i
px(n) = qx(n): py(n) = qy(n)
For i = n - 1 To 0 Step -1
px(i) = qx(i) - c(i) * px(i + 1)
py(i) = qy(i) - c(i) * py(i + 1)
Next i
'计算曲线上点的坐标
For i = 0 To n - 1
bx3 = (3 * (X(i + 1) - X(i)) / t(i + 1) - 2 * px(i) - px(i + 1)) / t(i + 1)
bx4 = ((2 * (X(i) - X(i + 1)) / t(i + 1) + px(i) + px(i + 1)) / t(i + 1)) / t(i + 1)
by3 = (3 * (Y(i + 1) - Y(i)) / t(i + 1) - 2 * py(i) - py(i + 1)) / t(i + 1)
by4 = ((2 * (Y(i) - Y(i + 1)) / t(i + 1) + py(i) + py(i + 1)) / t(i + 1)) / t(i + 1)
tt = 0
While (tt = t(i + 1))
cx = X(i) + (px(i) + (bx3 + bx4 * tt) * tt) * tt
cy = Y(i) + (py(i) + (by3 + by4 * tt) * tt) * tt
u1(num) = cx: v1(num) = cy: num = num + 1: tt = tt + 0.5
Wend
u1(num) = X(i + 1): v1(num) = Y(i + 1): num = num + 1
Next i
End Sub
Private Sub Command1_Click()
Dim i As Long
'Picture1.Scale (0, 0)-(640, 550)
DrawWidth = 3
Picture1.Cls
'If Check1.Value Then Command2_Click
'X(0) = 1
'Y(0) = 1
'X(t - 1) = 638
'Y(t - 1) = 548
Picture1.ForeColor = QBColor(10)
For i = 0 To t - 1
Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B
Picture1.Print i
Next i
Picture1.ForeColor = QBColor(12)
DrawWidth = 1
tspLine t - 1, 2, 0, 0, 0, 0
Picture1.PSet (u1(0), v1(0))
For i = 1 To num - 1
Picture1.Line -(u1(i), v1(i))
'For de = 1 To 12000: Next de 'Sleep 1
Next i
Picture1.ForeColor = QBColor(10)
For i = 0 To t - 1
Picture1.Line (X(i) - 1, Y(i) - 1)-(X(i) + 1, Y(i) + 1), QBColor(10), B
Picture1.Print i
Next i
End Sub
这个要用GDI+画。要看你.net版本。
以下是VS2005中的一段代码。
Me.PictureBox1.Height = 450
Me.PictureBox1.Width = 880
Dim gr As Graphics '定义画布
Dim bp As New Bitmap(880, 450) '定义位图,并进行赋值
Dim p As New Pen(Color.Black) '定义画笔
p.Width = 2 '宽度2
p.DashStyle = Drawing2D.DashStyle.Solid '样式直线
PictureBox1.Image = bp
gr = Graphics.FromImage(PictureBox1.Image)
gr.FillRectangle(Brushes.White, New Rectangle(0, 0, PictureBox1.Width, PictureBox1.Height))
gr.DrawLine(p, a, b, a, .Height - b) '绘制纵坐标
gr.DrawLine(p, a, .Height - b, .Width - a, .Height - b) '绘制横坐标
。net 其实还是很好绘制图形的
你可以看下 Graphics 类
Dim d As New Bitmap(Me.Width, Me.Height) ‘一个图片吧
Dim g As Graphics = Graphics.FromImage(d)’绘制 准备在这个图片是进行
然后 就是你绘制的东西了
线 就是 g.DrawLine()
圆 弧度 就用 g.DrawArc(Pens.Black, New Rectangle(0, 0, 400, 200), 0, 360)
复杂的就是 g.DrawBezier()
等 如果你用的是 VS的 编译 上面都有详细的参数说明
Dim d As New Bitmap(Me.Width, Me.Height)
Dim g As Graphics = Graphics.FromImage(d)
g.DrawArc(Pens.Black, New Rectangle(0, 0, 200, 200), 0, 360)
g.DrawLine(Pens.Red, New Point(0, 0), New Point(200, 200))
g.DrawLines(Pens.Green, New Point() {New Point(0, 0), New Point(50, 40), New Point(50, 80), New Point(90, 70), New Point(100, 400)})
g.DrawBezier(Pens.Yellow, New Point(0, 100), New Point(0, 0), New Point(200, 0）， New Point(200, 200))
g.Dispose()
Me.BackgroundImage = d