#include
#include
typedef struct BinaryTreeNode
{
int data;
struct BinaryTreeNode *Left;
struct BinaryTreeNode *Right;
}Node;
//创建二叉树,顺序依次为中间节点->左子树->右子树
Node* createBinaryTree()
{
Node *p;
int ch;
printf("输入data");
scanf("%d",&ch);
if(ch == 0) //如果到了叶子节点,接下来的左、右子树分别赋值为0
{
p = NULL;
}
else
{
p = (Node*)malloc(sizeof(Node));
p->data = ch;
p->Left = createBinaryTree(); //递归创建左子树
p->Right = createBinaryTree(); //递归创建右子树
}
return p;
}
//先序遍历
void preOrderTraverse(Node* root)
{
if( root )
{
printf("%d",root->data);
preOrderTraverse(root->Left);
preOrderTraverse(root->Right);
}
}
//中序遍历
void inOrderTraverse(Node* root)
{
if( root )
{
inOrderTraverse(root->Left);
printf("%d",root->data);
inOrderTraverse(root->Right);
}
}
//后序遍历
void lastOrderTraverse(Node* root)
{
if( root )
{
lastOrderTraverse(root->Left);
lastOrderTraverse(root->Right);
printf("%d",root->data);
}
}
//二叉树节点总数目
int Nodenum(Node* root)
{
if(root == NULL)
{
return 0;
}
else
{
return 1+Nodenum(root->Left)+Nodenum(root->Right);
}
}
//二叉树叶子节点数
int Leafnum(Node* root)
{
if(!root)
{
return 0;
}
else if( (root->Left == NULL) && (root->Right == NULL) )
{
return 1;
}
else
{
return (Leafnum(root->Left) + Leafnum(root->Right)) ;
}
}
int main()
{
int i;
Node *root = NULL;
root = createBinaryTree();
printf("二叉树建立成功");
printf("\n");
preOrderTraverse(root);
printf("\n");
inOrderTraverse(root);
printf("\n");
lastOrderTraverse(root);
printf("\n");
i = Leafnum(root);
printf("%d",i);
printf("\n");
i = Nodenum(root);
printf("%d",i);
return 0;
}
当前题目:普通二叉树的建立
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