vb.net数组的函数 vbs数组

vb.net 函数或者过程作为数组

thr_test(i) = New System.Threading.Thread(New System.Threading.ParameterizedThreadStart(Sub()

专注于为中小企业提供成都网站制作、做网站服务,电脑端+手机端+微信端的三站合一,更高效的管理,为中小企业龙华免费做网站提供优质的服务。我们立足成都，凝聚了一批互联网行业人才，有力地推动了1000+企业的稳健成长，帮助中小企业通过网站建设实现规模扩充和转变。

直接写过程代码

End Sub))

vb.net 返回一个数组的函数

public function createstringarr() as string()

return new string(){"d1","d2","d3","d4"}

end function

VB.net 如何编写一个可以返回数组的函数（过程）？

public function createstringarr() as string()

return new string(){"d1","d2","d3","d4"}

end function

vb.net 编写一个函数

注意：参数为动态数组；

Private Function MyF(ByRef d() As Integer)

ReDim d(4, 13) As Integer

Dim i As Integer

Dim j As Integer

Dim n As Integer

Dim MyNum(4) As Integer

For i = 1 To 4

MyNum(i) = 0

Next i

Randomize

For i = 1 To 4

For j = 1 To 13

n = Int(Rnd * 4 + 1)

Do While MyNum(n) = 13

n = Int(Rnd * 4 + 1)

Loop

d(i, j) = n

MyNum(n) = MyNum(n) + 1

Next j

Next i

End Function

vb.net中返回一个数组的函数的问题

给你一个简单的示例：

Option Explicit

Private Function GetRndInt() As Integer()

' 返回一个 Integer类型的数组

Dim i As Long, aTemp() As Integer

Randomize

ReDim aTemp(15)

For i = 0 To 15

aTemp(i) = Rnd() * 500

GetRndInt = aTemp

End Function

Private Sub Command1_Click()

Dim aTemp() As Integer

Dim i As Long

Me.Cls

aTemp = GetRndInt

Print "随机产生的数据为："

For i = 0 To UBound(aTemp)

Print i + 1, aTemp(i)

End Sub

运行效果：